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There are no tiebreakers in the draft lottery

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I had not realized this, until now, but there are no tiebreakers in the lottery, the way there are for playoff position. According to this post on wikipedia, "In the event that teams finish with the same record, each tied team receives the average of the total number of combinations for the positions that they occupy." So, if we tie with Utah for third-from-the-bottom in the standings, we'll get an average of the number of ping pong balls that third and fourth places would get. That's a substantial drop from what third place would get in its lonesome, so I guess I'll keep on rooting for us to lose.

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